The empirical formula of an organic compound is $C H_{2}$ . The mass of $1$ mole of it is $42$ g. The molecular formula of the compound is :

C_{4} H_{8}

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C_{2} H_{4}

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C_{3} H_{6}

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C H_{2}

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Solution

The correct option is C $C_{3} H_{6}$
As per given,
Empirical Formula Weight $= 12 + 2 = 14$ g.

Also, as we know,

$n = \frac{Molecular Weight}{Empirical Formula Weight} = \frac{42}{14} = 3$

$M o l e c u l a r F o r m u l a = (C H_{2})_{3} = C_{3} H_{6}$

Option C is correct.

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The empirical formula of an organic compound is CH2. The mass of 1 mole of it is 42 g. The molecular formula of the compound is :

The correct option is C C3H6As per given,Empirical Formula Weight =12+2=14 g.Also, as we know,n=Molecular WeightEmpirical Formula Weight=4214=3MolecularFormula=(CH2)3=C3H6Option C is correct.

The empirical formula of an organic compound is $C H_{2}$ . The mass of $1$ mole of it is $42$ g. The molecular formula of the compound is :

The correct option is C $C_{3} H_{6}$
As per given,
Empirical Formula Weight $= 12 + 2 = 14$ g.

Also, as we know,

$n = \frac{Molecular Weight}{Empirical Formula Weight} = \frac{42}{14} = 3$

$M o l e c u l a r F o r m u l a = (C H_{2})_{3} = C_{3} H_{6}$

Option C is correct.