Question

The end of a wire of length 0.5 m and radius ${10}^{-3}m$ is twisted through 0.80 radian. The shearing strain at the surface of wire will be :

• A. $1.6\times {10}^{-3}$
• B. $1.6\times {10}^3$
• C. $16\times {10}^3$
• D. $16\times {10}^6$

Answer 1

The correct option is A $1.6\times {10}^{-3}$

Given:
Length $l=0.5m$
Radius $r={10}^{-3}m$
Angle of twist $\theta$= 0.80 radian
$ShearStrain=\frac{r\theta }{l}$
$=\frac{{10}^{-3}\times 0.80}{0.5}=1.6\times {10}^{-3}$