The end product in the following series reaction is

${C H}_{3} C O O H N H_{3} - -- \to (A) H e a t - -- \to (B) F_{2} O_{2} - -- \to$

C H_{4}

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C H_{3} O H

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acetonitrile

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ammonium acelate

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Solution

The correct option is B $C H_{3} O H$
${C H}_{3} C O O H N H_{3} - -- \to C H_{3} C O O^{-} + N H_{4}^{+} H e a t - -- \to C H_{4} F_{2} O_{2} - -- \to C H_{3} O H$
Hence option (B) is correct.

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Similar questions

C H_{3} C O O H N H_{3} - -- \to A Δ - -- \to P_{2} O_{5} B

C H_{3} C O O H C a C O_{3} - --- \to A H e a t - -- \to B

B

C H_{3} C O O H N H_{3} - -- \to A Δ - \to B P_{2} O_{5} - -- \to C

C H_{4} + \frac{1}{2} O_{2} ⟶ C H_{3} O H

C H_{4}

C H_{3} O H

x

y

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