Question

The end-product in the reaction sequence would be:

Ethyl amine $\underset{}{\overset{HN{O}_2}{\to }}A\underset{}{\overset{P{Cl}_5}{\to }}B\underset{}{\overset{{NH}_3}{\to }}C$

• A. Ethyl cyanide
• B. Ethyl amine
• C. Methyl amine
• D. Acetamide

Answer 1

The correct option is B Ethyl amine

Ethylamine reactants with nitrous acid to form ethyl alcohol (compound A).

Ethyl alcohol reacts with $PC{l}_5$ to form ethyl chloride (compound B).

Ethyl chloride reacts with ammonia to form ethyl amine (compound C).

$C_2{H}_{5}N{H}_2\underset{}{\overset{HN{O}_2}{\to }}\underset{A}{C_2{H}_5-OH}\underset{}{\overset{P{Cl}_5}{\to }}\underset{B}{C_2{H}_{5}Cl}\underset{}{\overset{{NH}_3}{\to }}\underset{C}{C_2{H}_5-N{H}_2}$

Hence, the correct option is $B$