The end product in the reaction sequence would be:
Ethylamine $H N O_{2} - --- \to A P C l_{5} - -- \to B N H_{3} - -- \to C$

Ethyl cyanide

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Ethyl amine

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Methyl amine

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Acetamide

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B Ethyl amine
Ethylamine reactants with nitrous acid to from ethyl alcohol (compound A)

Ethyl alcohol reacts with $P C l_{5}$ to from ethyl chloride (compound B).

Ethyl chloride reacts with ammonia to from ethyl amine (compound C).

The reaction is as follows:

$C_{2} H_{5} N H_{2} H N O_{2} - --- \to C_{2} H_{5} - O H P C l_{5} - -- \to C_{2} H_{5} C l N H_{3} - -- \to C_{2} H_{5} - N H_{2}$

Suggest Corrections

Similar questions

H N O_{2} - --- \to A P {C l}_{5} - -- \to B {N H}_{3} - -- \to C

C_{2} H_{2} H g S O_{4} - ----- \to d i l . H_{2} S O_{4} P [O] - \to Q S O C l_{2} - --- \to R H_{2} - ------ \to P d - B a S O_{4} S

C H_{3} C H_{2} C H_{2} C H O N a B H_{4} - --- \to X P C l_{5} - -- \to Y (i) K C N - ---- \to (i i) H^{+} Z

Join BYJU'S Learning Program

Explore more

Join BYJU'S Learning Program