Question

The end product of $(4n+2)$ radioactive disintegration series is

• A. ${}_{82}P{b}^{208}$
• B. ${}_{82}P{b}^{206}$
• C. ${}_{82}P{b}^{207}$
• D. ${}_{83}B{i}^{210}$

Answer 1

The correct option is B ${}_{82}P{b}^{206}$

The mass no. on division by four gives a residue of 2.