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Standard VII

Chemistry

Sub-Atomic Particles

The end produ...

Question

The end products of uranium and actinium series are, respectively :

Pb-206, Pb-207

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Pb-206, Pb-208

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Pb-207, Pb-208

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Pb-206, Bi-208

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Solution

The correct option is B Pb-206, Pb-208
The end products of uranium and actinium series are Pb-206 and Pb-208, respectively.
Uranium series is 4n+2 series and actinium series is 4n+3 series.
$_{92} U^{238} - 8 α - - \to - 6 β_{82} P b^{206}$

$_{92} U^{235} - 4 α - - \to - 7 β_{82} P b^{208}$

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Similar questions

Q. The wavelengths of

K_{α}

X-rays for lead isotopes

P b^{208}, P b^{206}

and

P b^{204}

are

λ_{1}, λ_{2}

and

λ_{3}

respectively. Then

Q. Match the series (in List I) with starting element (in List II) and end element (in List III).

List I	List II	List III
4n	$_{94}^{241} P u$	$_{87}^{207} P b$
(4n+1)	$_{82}^{232} T h$	$_{83}^{209} B i$
(4n+2)	$_{92}^{235} U$	$_{83}^{209} P b$
(4n+3)	$_{92}^{238} U$	$_{82}^{206} P b$

_{92}^{238} U

by successive radioactive decays changes to

_{82}^{206} Pb

. A sample of uranium ore was analysed and found to contain 1:0 g

^{238} U

and 0.1 g

^{206} Pb

t_{1 / 2}

for

4.5 \times 10^{9} y e a r

.
Assuming the

^{206} Pb

has accumulated due to its decay of uranium, the age of ore is:

_{921} U^{238}

by successive radioactivity decays changes to

_{82} P b^{206}

.A sample of uranium ore was analyzed and found to contain 1.0g of

U^{238}

and

0.1

g of

P b^{206}

. Assuming that all the

P b^{206}

had accumulated due to decay of

U^{238}

,find out the age of the ore ?(Half life of

U^{238} = 4.5 * 10^{9} y e a r s) .

_{92} U^{238}

by successive radioactive decays changes to

_{82} {Pb}^{206}

. A sample of uranium ore was analyzed and found to contain 1.0 g of

U^{238}

and 0.1 g of

P b^{206}

. Assuming that all the

P b^{206}

had accumulated due to decay of

U^{238}

, find out the age of the ore. (Half life of

U^{238} = 4.5 \times 10^{9} y e a r s

)

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The end products of uranium and actinium series are, respectively :

The correct option is B Pb-206, Pb-208The end products of uranium and actinium series are Pb-206 and Pb-208, respectively.Uranium series is 4n+2 series and actinium series is 4n+3 series. 92U238−8α−−→−6β 82Pb206 92U235−4α−−→−7β 82Pb208

The correct option is B Pb-206, Pb-208
The end products of uranium and actinium series are Pb-206 and Pb-208, respectively.
Uranium series is 4n+2 series and actinium series is 4n+3 series.
$_{92} U^{238} - 8 α - - \to - 6 β_{82} P b^{206}$

$_{92} U^{235} - 4 α - - \to - 7 β_{82} P b^{208}$