The ends of latus rectum of parabola $x^{2} + 8 y = 0$ are

(-4, -2) and (4, 2)

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(4, -2) and (-4, 2)

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(-4, -2) and (4, -2)

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(4, 2) and (-4, 2)

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Solution

The correct option is C
(-4, -2) and (4, -2)

$x^{2} = - 8 y \Rightarrow a = - 2 .$ So , focus = (0,-2)

Ends of latus rectum = (4,-2) , (-4,-2) .

Trick: Since the ends of latus rectum lie on parabola , so only points (-4,-2) and (4,-2) satsify the parabola.

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