The energies of activation for forward and reverse reactions for $(A_{2} + B_{2} ⇌ 2 A B)$ are $180 k J$ mol $^{- 1}$ and $200 k J$ mol $^{- 1}$ respectively. The presence of a catalyst lowers the activation energy of both (forward and reverse) reactions by $100 k J$ mol $^{- 1}$ . The enthalpy change of the reaction $(A_{2} + B_{2} \to 2 A B)$ in the presence of catalyst will be (in kJ mol $^{- 1}$ )

300

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120

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280

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20

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Solution

The correct option is D $20$
In presence of catalyst, $E_{(f o r w a r d)} = 80 k J / m o l$ and $E_{(r e v e r s e)}$
$= 100 k J / m o l$ .
Therefore, $H_{(r e a c t i o n)}$ $= E_{(r e v e r s e)} - E_{(f o r w a r d)}$
$= 100 - 80$
$= 20 k J / m o l$ .

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Similar questions

Q. The energies of activation for

A_{2} + B_{2} ⇌ 2 A B

are

180 k J

m o l^{- 1}

forward and

200 k J

m o l^{- 1}

reverse reactions respectively. The presence of catalyst lowers the activation energies of both (forward and reverse) reactions

(A_{2} + B_{2} ⇌ 2 A B)

100 k J

m o l^{- 1} .

The magnitude of enthalpy change of the reaction in the presence of catalyst will be (in kJ

m o l^{- 1})

The energies of activation for forward and reverse reactions for $A_{2} + B_{2} ⇌ 2 A B$ are $180 k J m o l^{- 1}$ and $200 k J m o l^{- 1}$ respectively. The presence of a catalyst lowers activation energy of both reactions by $100 k J m o l^{- 1}$ . The enthalpy change of the reaction $(A_{2} + B_{2} \to 2 A B)$ in the presence of a catalyst will be (in kJ $m o l^{- 1}$ )