The energy consumed when 5 kW power is dissipated for 2 hrs is equal to __ kJ.

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Solution

We know that, Power = $\frac{E n e r g y d i s s i p a t e d}{T i m e}$

Energy dissipated = $P o w e r \times T i m e$ = $5 k W \times 2 h$ = $5000 \times 2 \times 3600$ J = 36000 kJ

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