Question

The energy difference between two electronic states is $43.56$ $kcal/mol$. The frequency of light emitted when the electron drops from higher orbit to lower orbit, is

• A. $9.14\times {10}^{14}cycle/sec$
• B. $45.7\times {10}^{14}cycle/sec$
• C. $91.4\times {10}^{14}cycle/sec$
• D. $4.57\times {10}^{14}cycle/sec$

Answer 1

The correct option is D $4.57\times {10}^{14}cycle/sec$

The energy difference between two electronic states is 43.56 kcal/mol. The frequency of light emitted when the electron drops from higher orbit to lower orbit, is $\nu =\frac{\Delta E}{h}=\frac{43.56kcal/mol\times 4184J/kcal}{6.626\times {10}^{-34}Js\times 6.023\times {10}^{23}}=4.57\times {10}^{14}cycle/sec$