Question

The energy (E) of a photon of light is related to its frequency (f) as E = hf. Here, h is Planck's constant. The value of Planck's constant is h = $6.62\times {10}^{-34}$ J-s in Sl units. Convert it into CGS system of units

Answer 1

Given Data:

The value of Planck's constant is $\text{h = 6.62 x 10-34 J-s}$

From, $n_1{u}_1=n_2{u}_2$

Here $J-s=\frac{kg{m}^2}{s^2}\times s$

And, $n_1=6.67\times 10^{-34}$

$n_1\frac{\left(1kg\right)\left(1m^2\right)}{s^2}\times s=n_2\frac{\left(1g\right)\left(1c{m}^2\right)}{s^2}\times s$

$n_1\frac{\left(1000g\right)\left(10000c{m}^2\right)}{s^2}\times s=n_2\frac{\left(1g\right)\left(1c{m}^2\right)}{s^2}\times s$

$6.62\times {10}^{-34}\times {10}^4\times \frac{\left(1000g\right)\left(10000c{m}^2\right)}{s^2}\times s=n_2\frac{\left(1g\right)\left(1c{m}^2\right)}{s^2}\times s$

$n_2=6.62\times {10}^{-34}\times {10}^3\times {10}^4$

$n_2=6.62\times {10}^{-27}$

$h=6.62\times {10}^{-27}gc{m}^2{s}^{-2}or,6.62\times {10}^{-27}erg-sec$