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Question

The energy expended in 1 kW electric heater in 30 seconds will be:

A
3×104 J
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B
3×104 erg
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C
3×104 eV
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D
0
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Solution

The correct option is C 3×104 J
Energy = Power×time
Power=1kW=1000W and time=30s
Energy=1000×30=30000 J=3×104 J

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