Question

The energy levels of an atom are shown below. Which of them will result in the transition of a photon of wavelength 275 nm?

Answer 1

Given that,

$\lambda =275nm=275\times {10}^{-9}m$

Energy is given by

$E=\frac{hc}{\lambda }$

$=\frac{6.6\times {10}^{-34}\times 3\times {10}^8}{275\times {10}^{-9}\times 1.6\times {10}^{-19}}$

$E=0.045\times {10}^2$

$E=4.5ev$

Out of all these energy levels no energy range will produce 275 nm. At 275 nm energy produced is 4.5 eV