Question

The energy levels of an atom of element X are shown in the diagram. Which one of the level transitions will results the emission of photons of wavelength 620 nm? Support your answer with mathematical calculations

Answer 1

Transition D will result in a wavelength of 620nm

Mathematics-

$\text{Energy difference in levels = energy of emitted photon=}\frac{1237.5}{x}eV$ where $x$ is wavelength in nanometer.

Given that $x=620nm$ so $Energy,E=\frac{1237.5}{620}eV=1.995eV$

Which is nearly $2eV$

We notice the difference in energy level for transition D is 2 eV given as $-1eV-(-3eV)=2eV$.