Question

The energy of a photon having wavelength 600 nm is:

• A. 1.77 eV
• B. 2.47 eV
• C. 3.50 eV
• D. 2.06 eV

Answer 1

The correct option is D 2.06 eV

From Planck's quantum theory,
$E=h\nu =\frac{hc}{\lambda }$
Where,
h = Planck's constant
c = Speed of light
$\lambda$ = Wavelength of the radiation

$\therefore E=\frac{6.6\times {10}^{-34}\times 3\times {10}^8}{600\times {10}^{-9}}=3.3\times {10}^{-19}J$
$\Rightarrow E=\frac{3.3\times {10}^{-19}}{1.6\times {10}^{-19}}eV=2.06eV$