The energy of a photon having wavelength 700 nm is:

1.77 eV

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2.47 eV

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700 eV

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3.57 eV

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Solution

The correct option is A 1.77 eV
$E = \frac{h c}{λ} = \frac{1242 e V . n m}{λ} = \frac{1242 e V . n m}{700 n m} = 1.77 e V$

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The energy of a photon having wavelength 700 nm is:

The correct option is A 1.77 eVE=hcλ=1242eV.nmλ=1242eV.nm700nm=1.77eV

The correct option is A 1.77 eV
$E = \frac{h c}{λ} = \frac{1242 e V . n m}{λ} = \frac{1242 e V . n m}{700 n m} = 1.77 e V$