The energy of a photon is 3 - 10-12 ergs- What is its wavelength in nm - h -6-62 - 10-27- erg-Sec- -c -3 - 1010 cm - s -1A- 662 nmB- 1324 nmC- 66-2 nmD- 6-62 nm

The correct option is A 662 nm λ = hc/E = 6.62 × 10^ 27 × 3 10^10/3 × 10^10 = 662 nm ...

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Question

The energy of a photon is $3 \times 10^{- 12} e r g s$ . What is its wavelength in nm ? ( $h$ = $6.62 \times 10^{- 27} e r g . S e c$ ; $c$ = $3 \times 10^{10} c m . s^{- 1})$

662 nm

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1324 nm

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66.2 nm

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6.62 nm

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Solution

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Similar questions

3 \times 10^{- 12}

6.62 \times 10^{- 27}

C = 3 \times 10^{10}

3 \times 10^{- 12} e r g s

h

6.625 \times 10^{- 27} e r g . S e c

C

3 \times 10^{10} c m . S e c^{- 1})

3 \times 10^{- 12}

19.875 \times 10^{- 13} e r g

c m^{- 1}

h

6.625 \times 10^{- 27} e r g . S e c

c

3 \times 10^{10} c m . s e c^{- 1}

(h = 6.62 \times 10^{- 27} e r g s e c .)

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