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Collision Theory

The energy of...

Question

The energy of activation of a reversible reaction is 6 kcal $(E_{a}$ forward) and heat of reaction is -3 kcal. The energy of activation for backward reaction in kcal is:

A

9

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B

-9

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C

3

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D

None of these

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Solution

The correct option is A 9
As we know, heat of reaction $= Δ H = E_{f} - E_{b}$

$E_{b} = E_{f} - Δ H = 6 - (- 3) = 9 k c a l =$ energy of activation for backward reaction

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