The energy of an electromagnetic radiation is $3 \times 10^{- 12} e r g s$ . What is its wavelength in nanometer?( $h$ = $6.625 \times 10^{- 27} e r g . S e c$ , $C$ = $3 \times 10^{10} c m . S e c^{- 1})$

400

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228.3

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3000

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662.5

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Solution

The correct option is D
662.5

$E = \frac{h c}{λ}$

$λ = \frac{h c}{E}$

= $\frac{6.625 \times 10^{- 25} \times 3 \times 10^{10}}{3 \times 10^{12}} \times 10^{7}$

= $662.5 n m$

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The energy of a photon is $3 \times 10^{- 12} e r g s$ . What is its wavelength in nm ? ( $h$ = $6.62 \times 10^{- 27} e r g . S e c$ ; $c$ = $3 \times 10^{10} c m . s^{- 1})$

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( h =

6.62 \times 10^{- 27}

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The energy of an electromagnetic radiation is 3 × 10−12 ergs. What is its wavelength in nanometer?(h = 6.625 × 10−27 erg.Sec, C = 3 × 1010 cm.Sec−1)

The correct option is D 662.5 E = hcλ λ = hcE = 6.625 × 10−25 × 3 × 10103 × 1012 × 107 = 662.5nm

The energy of an electromagnetic radiation is $3 \times 10^{- 12} e r g s$ . What is its wavelength in nanometer?( $h$ = $6.625 \times 10^{- 27} e r g . S e c$ , $C$ = $3 \times 10^{10} c m . S e c^{- 1})$

The correct option is D
662.5

$E = \frac{h c}{λ}$

$λ = \frac{h c}{E}$

= $\frac{6.625 \times 10^{- 25} \times 3 \times 10^{10}}{3 \times 10^{12}} \times 10^{7}$

= $662.5 n m$