The energy of an electron in the first Bohr orbit is -13.6 ev then find the energy of $H e^{+}$ in the same Bohr orbit.

27.2 ev

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-27.2 ev

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54.4 ev

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-54.4 ev

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Solution

The correct option is D -54.4 ev
Energy of $H e^{+}$ in same Bohr orbit $= - 13.6 \times Z^{2}$
For $H e^{+}, Z = 2$
$∴ E = - 13.6 \times (2)^{2} = - 54.4 e V$

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The energy of an electron in the first Bohr orbit is -13.6 ev then find the energy of He+ in the same Bohr orbit.

The correct option is D -54.4 evEnergy of He+ in same Bohr orbit =−13.6×Z2For He+, Z=2∴E=−13.6×(2)2=−54.4eV

The energy of an electron in the first Bohr orbit is -13.6 ev then find the energy of $H e^{+}$ in the same Bohr orbit.

The correct option is D -54.4 ev
Energy of $H e^{+}$ in same Bohr orbit $= - 13.6 \times Z^{2}$
For $H e^{+}, Z = 2$
$∴ E = - 13.6 \times (2)^{2} = - 54.4 e V$