The energy of an electron in the first Bohr orbit of H atom is -13.6 eV. The possible energy value for the electron in the excited states is:

-3.40 eV

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

-4.20 eV

No worries! We‘ve got your back. Try BYJU‘S free classes today!

-6.81 eV

No worries! We‘ve got your back. Try BYJU‘S free classes today!

-2.73 eV

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A -3.40 eV
The energy of an electron on Bohr orbits of hydrogen atoms is given by the expression
$E_{n} = - \frac{13.6 e V}{n^{2}}$
where, n takes only integral values.
For the first Bohr orbit n = 1, energy of electron is -13.6 eV.
Apart from that, only -3.4 eV is possible for n = 2

Suggest Corrections

Similar questions

The energy of an electron in the first Bohr orbit of H atom is -13.6eV. The possible energy value(s) of the excited state(s) for electrons in Bohr orbits to hydrogen is(are)

Q. The energy of an electron in the first Bohr orbit of

H

atom is

- 13.6 e V

. The possible energy value(s) of the excited state(s) for electrons in Bohr orbits of hydrogen is/are:

Q. The energy of an electron in the first Bohr orbit of H atom is -13.6 eV. The possible energy value(s) for the electron in the excited states(s) is (are):

Join BYJU'S Learning Program

Explore more

Bohr's Model of a Hydrogen Atom

Standard XII Chemistry

Join BYJU'S Learning Program

The energy of an electron in the first Bohr orbit of H atom is -13.6 eV. The possible energy value for the electron in the excited states is:

The correct option is A -3.40 eVThe energy of an electron on Bohr orbits of hydrogen atoms is given by the expression En=−13.6 eVn2 where, n takes only integral values. For the first Bohr orbit n = 1, energy of electron is -13.6 eV. Apart from that, only -3.4 eV is possible for n = 2