The energy of an electron in the first Bohr orbit of H-atom is -13.6 eV. The possible energy value(s) of the excited state(s) for electrons in Bohr orbits of hydrogen is:
A
−3.4eV
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B
−4.2eV
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C
−6.8eV
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D
+6.8eV
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Solution
The correct option is B−3.4eV Since we know that the energy of electron in H-atom En=−13.6n2eV where, n=1,2,3,..... In excited states, E2=−13.64=−3.4eV E3=−13.69=−1.51eVetc.