Question

The energy of an electron in the first Bohr orbit of H atom is -13.6 eV. The possible energy value for the electron in the excited states is:

• A. -3.40 eV
• B. -4.20 eV
• C. -6.81 eV
• D. -2.73 eV

Answer 1

The correct option is A -3.40 eV

The energy of an electron on Bohr orbits of hydrogen atoms is given by the expression
$E_n=-\frac{13.6eV}{n^2}$
where, n takes only integral values.
For the first Bohr orbit n = 1, energy of electron is -13.6 eV.
Apart from that, only -3.4 eV is possible for n = 2