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Question

The energy of an electron in the first Bohr orbit of H-atom is 13.6 eV. The possible energy value(s) of the excited state(s) for electrons in Bohr's orbits of hydrogen is (are):

A
3.4 eV
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B
4.2 eV
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C
6.8 eV
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D
+6.8 eV
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Solution

The correct option is A 3.4 eV
The energy of an electron in a Bohr atom is expressed as
E=kZ2n2
where, k = Constant,
Z = Atomic number,
n = Orbit number
= 13.6 eV for H(n=1)
when n=2 , E2=13.622 eV=3.40 eV
(Where n can have only integral value 1,2,3,)
For higher integral values of n(n>2), the value of E will be lesser in magnitude as compared to 3.40 eV. So none of the options will match.


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