The energy of an electron in the first energy level of $H$ atom is $- 13.6$ eV. The possible energy value of the excited state for the electron in He $^{+}$ is:

27.2

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- 13.6

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- 27.2

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- 54.4

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Solution

The correct option is D $- 54.4$ eV
The possible energy value of the excited state for an electron in the $H e^{+}$ ion is $- 13.6 \times Z^{2}$ .

where z = atomic number

$= - 13.6 \times 2^{2}$

$= - 13.6 . \times 4$

$= - 54.4$ eV.

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The energy of an electron in the first energy level of H atom is −13.6 eV. The possible energy value of the excited state for the electron in He+ is:

The correct option is D −54.4 eVThe possible energy value of the excited state for an electron in the He+ ion is −13.6×Z2.where z = atomic number=−13.6×22=−13.6.×4=−54.4 eV.

The energy of an electron in the first energy level of $H$ atom is $- 13.6$ eV. The possible energy value of the excited state for the electron in He $^{+}$ is:

The correct option is D $- 54.4$ eV
The possible energy value of the excited state for an electron in the $H e^{+}$ ion is $- 13.6 \times Z^{2}$ .

where z = atomic number

$= - 13.6 \times 2^{2}$

$= - 13.6 . \times 4$

$= - 54.4$ eV.