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Alpha Decay

The Energy of...

Question

The Energy of an excited H-atom is -3.4 eV. Calculate angular momentum of e^-.

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Solution

$E n e r g y = - 3.4 e V E n e r g y = - \frac{13.6 Z^{2}}{n^{2}} F o r h y d r o g e n, Z = 1 H e n c e, - 3.4 = \frac{- 13.6}{n^{2}} n^{2} = 4, n = 2 A n g u l a r m o m e n t u m = n (\frac{h}{2 π}) = 2 \times (\frac{6.626 \times 10^{- 34} J s}{2 π}) = 2.11 \times 10^{- 34} J s$

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