The energy of electron in the first orbit of hydrogen atom is $- 13.6$ eV. Its potential energy is :

13.6

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27.2

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- 27.2

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- 6.8

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Solution

The correct option is B $- 27.2$ eV
Total energy of electron in first orbit $E_{1} = - 13.6 e V$

Potential energy of electron in the first orbit $U = 2 E_{1}$

$∴$ $U = 2 \times (- 13.6 e V) = - 27.2 e V$

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