The energy of gamma $(γ)$ ray photon is $E_{γ}$ and that of an X-ray photon is $E_{X}$ . If the visible light photon has an energy of $E_{v}$ , then we can say that:

E_{X} > E_{γ} > E_{v}

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E_{γ} > E_{v} > E_{X}

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E_{γ} > E_{X} > E_{v}

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E_{X} > E_{v} > E_{γ}

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Solution

The correct option is D $E_{γ} > E_{X} > E_{v}$
Energy of a photon $E = h ν$
where $ν$ is the frequency of the photon and $h$ is Planck's constant
$⟹$ $E \propto ν$
As $ν_{γ} > ν_{X} > ν_{v}$
$⟹$ $E_{γ} > E_{X} > E_{v}$

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The energy of gamma (γ) ray photon is Eγ and that of an X-ray photon is EX. If the visible light photon has an energy of Ev, then we can say that:

The correct option is D Eγ>EX>EvEnergy of a photon E=hν where ν is the frequency of the photon and h is Planck's constant⟹ E∝νAs νγ>νX>νv⟹ Eγ>EX>Ev

The energy of gamma $(γ)$ ray photon is $E_{γ}$ and that of an X-ray photon is $E_{X}$ . If the visible light photon has an energy of $E_{v}$ , then we can say that:

The correct option is D $E_{γ} > E_{X} > E_{v}$
Energy of a photon $E = h ν$
where $ν$ is the frequency of the photon and $h$ is Planck's constant
$⟹$ $E \propto ν$
As $ν_{γ} > ν_{X} > ν_{v}$
$⟹$ $E_{γ} > E_{X} > E_{v}$