Question

The energy of gamma $\left(\gamma \right)$ ray photon is $E_{\gamma }$ and that of an X-ray photon is $E_X$. If the visible light photon has an energy of $E_v$, then we can say that:

• A. $E_X>E_{\gamma }>E_v$
• B. $E_{\gamma }>E_v>E_X$
• C. $E_{\gamma }>E_X>E_v$
• D. $E_X>E_v>E_{\gamma }$

Answer 1

Answer: (C)

$E_{\gamma }>E_X>E_v$

Energy of a photon $E=h\nu$

where $\nu$ is the frequency of the photon and $h$ is Planck's constant

$⟹$ $E\propto \nu$

As ${\nu }_{\gamma }>{\nu }_X>{\nu }_v$

$⟹$ $E_{\gamma }>E_X>E_v$