The energy of hydrogen atom in nth orbit is $E_{n}$ , then the energy in nth orbit of singly ionised helium atom will be

4 E_{n}

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\frac{E_{n}}{4}

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2 E_{n}

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\frac{E_{n}}{2}

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Solution

The correct option is A $4 E_{n}$
By using $E = - \frac{13.6 Z^{2}}{n^{2}} \Rightarrow \frac{E_{H}}{E_{H e}} = {(\frac{Z_{H}}{Z_{H e}})}^{2} = {(\frac{1}{2})}^{2} \Rightarrow E_{H e} = 4 E_{n}$

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The energy of hydrogen atom in nth orbit is En, then the energy in nth orbit of singly ionised helium atom will be

The correct option is A 4EnBy using E=−13.6Z2n2⇒EHEHe=(ZHZHe)2=(12)2⇒EHe=4En

The energy of hydrogen atom in nth orbit is $E_{n}$ , then the energy in nth orbit of singly ionised helium atom will be

The correct option is A $4 E_{n}$
By using $E = - \frac{13.6 Z^{2}}{n^{2}} \Rightarrow \frac{E_{H}}{E_{H e}} = {(\frac{Z_{H}}{Z_{H e}})}^{2} = {(\frac{1}{2})}^{2} \Rightarrow E_{H e} = 4 E_{n}$