The energy of separation of an electron is $30.6 e V$ moving in an orbit of $L i^{2 +}$ . The number of waves made by the electron in one complete revolution in the orbit is:

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Solution

As the energy of separation of an electron is $30.6 e V$ means it has this much energy in the ground state.
By calculation, as $E = - \frac{13.6 Z^{2}}{n^{2}}$ ;
Here $Z$ is $3$ , $n = 2$
So, the number of waves made by the electron in one complete revolution in the orbit is $2$ .

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The energy of separation of an electron is 30.6 eV moving in an orbit of Li2+. The number of waves made by the electron in one complete revolution in the orbit is:

As the energy of separation of an electron is 30.6eV means it has this much energy in the ground state.By calculation, as E=−13.6Z2n2;Here Z is 3, n=2So, the number of waves made by the electron in one complete revolution in the orbit is 2.

The energy of separation of an electron is $30.6 e V$ moving in an orbit of $L i^{2 +}$ . The number of waves made by the electron in one complete revolution in the orbit is:

As the energy of separation of an electron is $30.6 e V$ means it has this much energy in the ground state.
By calculation, as $E = - \frac{13.6 Z^{2}}{n^{2}}$ ;
Here $Z$ is $3$ , $n = 2$
So, the number of waves made by the electron in one complete revolution in the orbit is $2$ .