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Byju's Answer
Standard XII
Chemistry
Introduction to Atomic Structure
The energy of...
Question
The energy of the electron in the second and third Bohr orbits of hydrogen atom is
−
5.42
×
10
−
12
e
r
g
and
−
2.41
×
10
−
12
e
r
g
respectively. Calculate the wavelength of the emitted radiation when the electron drops from third to second orbit.
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Solution
1
e
r
g
=
10
−
7
J
⇒
E
2
=
5.42
×
10
−
19
J
=
3.38
e
V
E
3
=
2.41
×
10
−
19
J
=
1.50
e
V
Δ
E
3
→
2
=
3.38
−
1.5
=
1.88
e
V
h
×
c
=
1242
e
V
/
n
m
Δ
E
3
→
2
=
h
c
λ
=
1242
λ
(
n
m
)
=
1.88
⇒
λ
=
660.638
n
m
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1
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The energy of an electron in the second and the third Bohr orbit of hydrogen atom is
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