Question

The energy of the reaction $L{i}^7+p\to 2H{e}^4$ is (the binding energy per nucleon in $L{i}^7$ and $H{e}^4$ nuclei are $5.60\text{MeV}$ and $7.06\text{MeV}$ respectively.

• A. $17.3\text{MeV}$
• B. $1.73\text{MeV}$
• C. $1.46\text{MeV}$
• D. depends on binding energy of proton

Answer 1

The correct option is A $17.3\text{MeV}$

Energy of proton $=\text{Binding energy of}\left(H{e}^4\right)-\text{Binding energy of}\left(L{i}^7\right)$
$=7.60\times 4\times 2-5.60\times 7$
$=17.3\text{MeV}$