The energy of the second Bohr orbit of hydrogen atom is - 3.41 eV. The energy of the second orbit of $H e^{+}$ would be:

-0.85eV

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-13.6eV

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-1.70eV

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-6.82eV

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Solution

The correct option is D -13.6eV
The energy of electron in Bohr's model is directly proportional to $Z^{2} / n^{2}$ .
Therefore the energy of electron in 2nd orbit of $H e^{+}$ is 4 times the energy of electron in 2nd orbit of Hydrogen.
Note: Bohr's model can be applied to single electrons system only.

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The energy of an electron in the first Bohr orbit of H - atom is - 13.6 eV. Then, which of the following statement(s) is/are correct for $H e^{+}$ ?

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