Question

The energy of the second stationary state in $L{i}^{+2}$ ion is -11.025 x ${10}^{-18}$ J. Find ionization energy (in J/mole) for $H{e}^{+}$ ions in its ground state:

Answer 1

$I.E$ of ${He}^{+}=+13.6\times \frac{2^2}{1^2}=+13.6\times \frac{2^2}{1^2}eV$

$=(+13.6\times 4\times 1.6\times {10}^{-19})J$

$=87.14\times {10}^{-19}J$