wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The energy radiated by a black body at 2300 K is found to have a maximum intensity at a wavelength 1260 nm, its emissive power being 8000 W/m2. When the body is cooled to a temperature T K, the emissive power is found to decrease to 500 W/m2. Find the temperature T.

A
1000 K
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1500 K
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1050 K
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
1150 K
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 1150 K
λmax=1260×109 m at T1=2300 K
Also, T2=T K
We know that ET4
E1E2=(T1T2)4T2=T1[E2E1]1/4
T2=2300×[5008000]1/4
T2=2300×12=1150 K

flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon