Question

The energy released by the fission of one uranium atom is $200MeV$. The number of fission per second required to produce $6.4W$ power is

• A. $2\times {10}^{11}$
• B. ${10}^{11}$
• C. ${10}^{10}$
• D. $2\times {10}^{10}$

Answer 1

Answer: (A)

$2\times {10}^{11}$

Let there is $n$ number of fission per second produces a power of $6.4W$, then
$n\times 200\times {10}^6\times 1.6\times {10}^{-19}J/s=6.4J/s$
$\therefore n=\frac{6.4}{200\times {10}^{-3}\times 1.6}=\frac{4}{2\times {10}^{-11}}=2\times {10}^{11}$.