The energy released per fission of 92U235 is 200 Mev. The fission rate of 92U235 required to produce 2 watt power is
A
1.25 x1026 per second
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B
2.56x 1026 per second
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C
1.25x 10 13per second
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D
6.25 x1010 per second
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Solution
The correct option is D 6.25 x1010 per second 1 fission causes 200MeV. 1MeV=1.6×10−13J i.e. 200MeV=3.2×10−11J To generate 2W, we need 23.2×10−11 fission every second.