Question

The energy released per fission of a ₉₂U²³⁵ nucleus is nearly

• A. 200 J
• B. 200 eV
• C. 200 MeV
• D. none of these

Answer 1

The correct option is C

200 MeV

Explanation

1. The nuclear fission reaction of Uranium(₉₂U²³⁵ ) is represented as ${}_{92}\mathrm{U}^{236}+{}_0\mathrm{n}^1\to {}_{56}\mathrm{Ba}+{}_{36}\mathrm{Kr}+3{}_0\mathrm{n}^1$
2. Mass of reactants $=234.39+1.01=235.4\mathrm{amu}$
3. Mass of products $=45.28+88.89+3(1.01)=235.2amu$
4. The energy released = differences in the masses of reactants and products $=235.4-235.2=0.2\times 931=200MeV(approx.)$

Hence, the energy released per fission of a ₉₂U²³⁵ nucleus is nearly 200 MeV.

So, option C is correct.