Question

The energy released per fission of Uranium is 200 MeV. Determine the number of fission per second required to generate 2MW power.

• A. $6.25\times {10}^{16}$
• B. $0.25\times {10}^{16}$
• C. $1.25\times {10}^{16}$
• D. $25\times {10}^{16}$

Answer 1

The correct option is A $6.25\times {10}^{16}$

Energy obtained per fission
$=200MeV=200\times 1.6\times {10}^{-13}J=3.2\times {10}^{-11}J$
no. of fission per second required
$=\frac{2\times {10}^6}{3.2\times {10}^{-11}}=6.25\times {10}^{16}$.