1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard X
Physics
Nuclear Fusion
The energy re...
Question
The energy released when a positron is annihilated is :
A
0.52MeV
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
5.3MeV
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
185MeV
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
200MeV
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is
B
0.52MeV
Mass of electron
=
mass of positron
E
=
(
Δ
m
)
c
2
=
(
9.1
×
10
−
31
1.6
×
10
−
27
×
931.478
M
e
V
c
2
)
c
2
=
0.52
M
e
V
Suggest Corrections
0
Similar questions
Q.
When an electron-positron pair annihilates, the energy released is about :
Q.
Calculate the energy released when an electron annihilates a positron.
Q.
If an electron and positron annihilate, then the energy released is
Q.
The minimum amount of energy released in annihilation of electron-positron is.
Q.
When an electron and a positron are annihilated, then the number of photons produced is
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Nuclear Energy
PHYSICS
Watch in App
Explore more
Nuclear Fusion
Standard X Physics
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app