The energy required to break 76 gm gaseous fluorine into free gaseous atom is 180 Kcal at $25^{0} C$ . The bond energy of F-F bond will be:

180 Kcal

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90 Kcal

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45 Kcal

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104 kcal

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Solution

The correct option is A 90 Kcal
$F_{2} \to 2 F$
76 gram $F_{2}$ needs 180 Kcal energy
38 gram $F_{2}$ needs enesrgy $= 180 \times 38 / 76 = 90$ kcal

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