Question

The energy stored in coil carrying current I s U. If current is halved, then energy stored in the coil will be

Answer 1

$$\begin{gathered} Energystored,U=\frac{1}{2}L{i}^2 \\ i=i/2 \\ U\text{'}=\frac{1}{2}L(\frac{i}{2}{)}^2 \\ U\text{'}=\frac{U}{4} \\ EnergywillbeOnefourthwhencurrentbecomesHalf. \end{gathered}$$