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Question
The engine of a motorcycle can produce a max acc. of 5 mtr per sec square. Its brakes can produce a maximum retardation of 10 mtr per sec square. What is the min time in which it can cover a distance of 1.5km.?
The engine of a motorcycle can produce a max acc. of 5 mtr per sec square. Its brakes can produce a maximum retardation of 10 mtr per sec square. What is the min time in which it can cover a distance of 1.5km.?
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Solution
The answer is 30s.
there is a formula for this type of questions - [(αβ)/2(α+β)] * t2 = s
where
α = Maximum acceleration
t = time
β = Maximum retardation
s = distance
So,
[5×10/2(5+10)]×t^2=1500
[50/30]×t^2=1500
t^2=(1500×30)/50
t^2=30×30
t=30s
The answer is 30s.
there is a formula for this type of questions - [(αβ)/2(α+β)] * t2 = s
where
α = Maximum acceleration
t = time
β = Maximum retardation
s = distance
So,
[5×10/2(5+10)]×t^2=1500
[50/30]×t^2=1500
t^2=(1500×30)/50
t^2=30×30
t=30s
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