The enolic form acetone contains :

σ -

bonds

2 π -

bond and 1 lone pairs.

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σ -

bonds

2 π -

bond and 2 lone pairs.

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σ -

bonds

2 π -

bond and 2 lone pairs.

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σ -

bonds

1 π -

bond and 2 lone pairs.

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Solution

The correct option is D 9 $σ -$ bonds $1 π -$ bond and 2 lone pairs.
The enol form of acetone is $C H_{2} = C (O H) - C H_{3}$ ,
It contains 9 $σ -$ bonds $1 π -$ bond and 2 lone pairs.

Hence, option D is correct.

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