The enolic form of acetone contains

9 sigma bonds, 1 pi bond and 2 lone pairs

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8 sigma bonds, 2 pi bonds and 2 lone pairs

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10 sigma bonds, 1 pi bond and 1 lone pair

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9 sigma bonds, 2 pi bonds and 1 lone pair

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Solution

The correct option is B 9 sigma bonds, 1 pi bond and 2 lone pairs

Hence, $σ$ bonds $= 9$ ; $π$ -bonds $= 1$ ; lone pair $= 2$

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