Question 7
The enrolment in a school during six consecutive years was as follows:
1555, 1670, 1750, 2013, 2540, 2820. Find the mean enrolment of the school for this period.

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Solution

$M e a n e n r o l m e n t = \frac{S u m o f n u m b e r s o f e n r o l e m e n t i n a l l t h e y e a r s}{T o t a l n u m b e r o f y e a r s} = \frac{1555 + 1670 + 1750 + 2013 + 2540 + 2820}{6} = \frac{12348}{6} = 2058$
Thus, the mean enrolment of the school is 2,058

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Arithmetic Mean and Range

Standard VII Mathematics

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Question 7 The enrolment in a school during six consecutive years was as follows: 1555, 1670, 1750, 2013, 2540, 2820. Find the mean enrolment of the school for this period.

Mean enrolment=Sum of numbers of enrolement in all the yearsTotal number of years=1555+1670+1750+2013+2540+28206=123486=2058 Thus, the mean enrolment of the school is 2,058

Question 7
The enrolment in a school during six consecutive years was as follows:
1555, 1670, 1750, 2013, 2540, 2820. Find the mean enrolment of the school for this period.

$M e a n e n r o l m e n t = \frac{S u m o f n u m b e r s o f e n r o l e m e n t i n a l l t h e y e a r s}{T o t a l n u m b e r o f y e a r s} = \frac{1555 + 1670 + 1750 + 2013 + 2540 + 2820}{6} = \frac{12348}{6} = 2058$
Thus, the mean enrolment of the school is 2,058