The enrolment in a school during six consecutive years was as follows:
1555, 1670, 1750, 2013, 2540, 2820. Find the mean enrolment of the school for this period.

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Solution

$M e a n e n r o l m e n t = \frac{S u m o f n u m b e r s o f e n r o l e m e n t i n a l l t h e y e a r s}{T o t a l n u m b e r o f y e a r s} = \frac{1, 555 + 1, 670 + 1, 750 + 2, 013 + 2, 540 + 2, 820}{6} = \frac{12, 348}{6} = 2, 058$
Thus, the mean enrolment of the school is 2,058

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The enrolment in a school during six consecutive years was as follows: 1555, 1670, 1750, 2013, 2540, 2820. Find the mean enrolment of the school for this period.

Mean enrolment=Sum of numbers of enrolement in all the yearsTotal number of years=1,555 + 1,670 + 1,750 + 2,013 + 2,540 + 2,8206=12,3486=2,058 Thus, the mean enrolment of the school is 2,058

The enrolment in a school during six consecutive years was as follows:
1555, 1670, 1750, 2013, 2540, 2820. Find the mean enrolment of the school for this period.

$M e a n e n r o l m e n t = \frac{S u m o f n u m b e r s o f e n r o l e m e n t i n a l l t h e y e a r s}{T o t a l n u m b e r o f y e a r s} = \frac{1, 555 + 1, 670 + 1, 750 + 2, 013 + 2, 540 + 2, 820}{6} = \frac{12, 348}{6} = 2, 058$
Thus, the mean enrolment of the school is 2,058