The enthaipy of fusion of ice is 6-02 kj - mole the heat capacity of water is 4-18 joule g -1 C -1 what is the smallest number of ice cubes at 00 C each containing one mole of water that are needed to cool 500 g of liquid water from 20- C -30- C ans -7 how -

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Standard XII

Chemistry

Elevation in Boiling Point

the enthaipy ...

Question

the enthaipy of fusion of ice is 6.02 kj/mole the heat capacity of water is 4.18 joule g^-1C^-1 what is the smallest number of ice cubes at 0⁰C each containing one mole of water that are needed to cool 500 g of liquid water from 20^oC - 30^oC

ans =7 how ?

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Solution

The only unknown is the conversion from 500g of H2O to moles of H2O At wt of H = 1
at wt of O =16 so H2O = 18g/mole
500g/18g/mole = 27.8moles
to cool 27.8 moles 20deg = 27.8mole x 75.4 J/mole.deg x 20 deg
41,922J are needed to cool the water

41.922kJ/6.02kJ = 7 therefore 7 moles of ice cubes (7 cubes) will be needed

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the enthaipy of fusion of ice is 6.02 kj/mole the heat capacity of water is 4.18 joule g-1C-1 what is the smallest number of ice cubes at 00C each containing one mole of water that are needed to cool 500 g of liquid water from 20oC - 30oC ans =7 how ?

the enthaipy of fusion of ice is 6.02 kj/mole the heat capacity of water is 4.18 joule g^-1C^-1 what is the smallest number of ice cubes at 0⁰C each containing one mole of water that are needed to cool 500 g of liquid water from 20^oC - 30^oC

ans =7 how ?