The enthalpies for the following reactions at 25oC are given: 12H2(g)+12O2(g)→OH(g);ΔH=10.06kcal H2(g)→2H(g);ΔH=104.18kcal O2(g)→2O(g);ΔH=118.32kcal Calculate the O−H bond energy in the OH group.
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Solution
Required equation is H(g)+O(g)→O−H(g);ΔH=? Given: 12H2(g)+12O2(g)→OH(g);ΔH=+10.06kcal H(g)→12H2(g);ΔH=−52.09kcal O(g)→12O2(g);ΔH=−52.16kcal Adding H(g)+O(g)→OH(g);ΔH=−101.19kcal